func c(var s:Int)->String{var r="";while(s != 4){r+="\(s)";let f=NSNumberFormatter();f.numberStyle=NSNumberFormatterStyle.SpellOutStyle;let v=f.stringFromNumber(s)!;s=v.stringByReplacingOccurrencesOfString("[- ]",withString:"",options:NSStringCompareOptions.RegularExpressionSearch,range:Range<String.Index>(start:v.startIndex,end:v.endIndex)).utf8.count+(s<0 ?3:0);r+=" is \(s) and "};return r+"4 is the magic number"}  

100003 är 23 och 23 är 11 och 11 är 6 och 6 är 3 och 3 är 5 och 5 är 4 och 4 är det magiska numret

Ungolfed

 func a(var s: Int) -> String{ var r = "" while(s != 4){ r+="\(s)" let f = NSNumberFormatter() f.numberStyle = NSNumberFormatterStyle.SpellOutStyle let v = f.stringFromNumber(s)! s = v.stringByReplacingOccurrencesOfString( "[- ]", withString: "", options: NSStringCompareOptions.RegularExpressionSearch, range: Range<String.Index>(start: v.startIndex, end: v.endIndex) ).utf8.count + (s < 0 ? 3 : 0) r+=" is \(s) and " } return r+"4 is the magic number" }  

Kommentarer

• NSStringCompareOptions.RegularExpressionSearch Och jag trodde JS ' s String.fromCharCode var omfattande. : P
• Python och Ruby: string.replace.Snabb: String.stringByReplacingOccurrencesOfString

Haskell, 285 – 180 = 105 byte

Det finns faktiskt ingen inbyggd alls för att visa nummer. Jag är fortfarande missnöjd med poängen. Kommentera gärna. Jag kommer dock att experimentera vidare. Fortfarande är poängen bättre än Swifts poäng

 c n|n<0=8+c(-n)|n>999=r 1000+8|n>99=7+r 100|n>19=r 10+2-g[30..59]+g[20..29]|n>15=r 10-1|2>1=[0,3,3,5,4,4,3,5,5,4,3,6,6,8,8,7]!!n where{g=fromEnum.elem n;r k=c(mod n k)+c(div n k)} m 4="4 is the magic number" m 0="0 is 4 and "++m 4 m n=show n++" is "++show(c n)++" and "++m(c n)  

användning

 m 7 "7 is 5 and 5 is 4 and 4 is the magic number" m 999999 "999999 is 50 and 50 is 5 and 5 is 4 and 4 is the magic number"  

Förklaring.

m är trivialt, men c är inte. c är funktionen för att räkna antalet tecken det engelska namnet av nummer.

c n |n<0=8+c(-n) -- Add word "negative" in front of it, the length is 8 |n>999=r 1000+8 -- the english name for number with form xxx,yyy is xxx thousand yyy |n>99=7+r 100 -- the english name for number with form xyy is x hundred yy |n>19=r 10+2-g[30..59]+g[20..29] -- the english name for number with form xy with x more -- than 1 is x-ty. However *twoty>twenty, -- *threety>thirty, *fourty>forty, *fivety>fifty. |n>10=r 10-1-g(15:18:[11..13]) -- the english name for number with form 1x is x-teen. -- However, *oneteen>eleven, *twoteen>twelve, -- *threeteen>thirteen, *fiveteen>fifteen, -- *eightteen>eighteen |2>1=[0,3,3,5,4,4,3,5,5,4,3]!!n -- for number 0-10, the length is memorized. 0 is 0 -- because it is omitted. Input zero is handled -- separately. If we defined 0 to be 4, then -- 20 => twenty zero. where g =fromEnum.elem n -- Check if n is element of argument array, if true, 1 else 0 r k=c(mod n k)+c(div n k) -- Obvious. 

Kommentarer

• Åh ja? Jo, Swift har … uhm. .. en högre poäng … (jag ' jag är inte särskilt bra på comebacks)

C, 268 – 180 = 88 byte

 #define t(x,o)n<x?o:f(n/x)+(n%x?f(n%x):0) char*i="4335443554366887798866555766";f(n){return t(1000,t(100,n<20?n<0?8+f(-n):i[n]-48:i[n/10+18]-48+(n%10?f(n%10):0))+7)+8;}main(n){for(scanf("%d",&n);n^4;n=f(n))printf("%d is %d and ",n,f(n));puts("4 is the magic number");}  

Prova här .

Ungolfed

 /* Encode number length in string (shorter representation than array) */ char*i="4335443554366887798866555766"; f(n) { return n < 1000 ? n < 100 ? n < 20 ? n < 0 ? 8 + f(-n) /* "Negative x" */ : i[n] - 48 /* "x" */ : i[n/10+18] + (n%10 ? f(n%10) : 0) /* 20-99 */ : f(n/100) + (n%100 ? f(n%100) : 0) + 7 /* x hundred y */ : f(n/1000) + (n%1000 ? f(n%1000) : 0) + 8; /* x thousand y */ } main(n) { /* Keep printing until you get to the magic number */ for(scanf("%d",&n);n^4;n=f(n)) printf("%d is %d and ",n,f(n)); puts("4 is the magic number"); }  

Java, 800 – 150 = 650 byte

class G{static String e="",i="teen",j="ty",k="eigh",y="thir",d="zero",l="one",n="two",m="three",h="four",s="five",c="six",t="seven",b=k+"t",g="nine",D="ten",L="eleven",N="twelve",M=y+i,H=h+i,S="fif"+i,C=c+i,T=t+i,B=k+i,G=g+i,o="twen"+j,p=y+j,q="for"+j,r="fif"+j,u=c+j,v=t+j,w=k+j,x=g+j,A=" ",O=" hundred ",z,E;public static void main(String a[]){z=e;int l=new Integer(a[0]);do{E=a(l,1,e);l=E.replace(A,e).length();z=z+E+" is "+a(l,1,e)+" and ";}while(l!=4);System.out.print(z+h+" is the magic number");}static String a(int P,int _,String Q){String[]f={e,l,n,m,h,s,c,t,b,g,D,L,N,M,H,S,C,T,B,G,e,D,o,p,q,r,u,v,w,x};int R=20,X=10,Y=100,Z=1000;return P==0?(_>0?d:e):(P<R?f[P]+Q:(P<Y?(f[R+(P/X)]+" "+a(P%X,0,e)).trim()+Q:(P<Z?a(P/Y,0,O)+a(P%Y,0,e)+Q:a(P/Z,0," thousand ")+a((P/Y)%X,0,O)+a(P%Y,0,e)+Q)));}} 

Avgolfad

class G { static String e="",i="teen",j="ty",k="eigh",y="thir",d="zero",l="one",n="two",m="three",h="four",s="five",c="six",t="seven",b=k+"t",g="nine",D="ten",L="eleven",N="twelve",M=y+i,H=h+i,S="fif"+i,C=c+i,T=t+i,B=k+i,G=g+i,o="twen"+j,p=y+j,q="for"+j,r="fif"+j,u=c+j,v=t+j,w=k+j,x=g+j,A=" ",O=" hundred ",z,E; public static void main(String a[]){ z = e; int l = new Integer(a[0]); do { E = a(l,1,e); l = E.replace(A,e).length(); z = z+E+" is "+a(l,1,e)+" and "; } while(l!=4); System.out.println(z+h+" is the magic number"); } static String a(int P,int _,String Q) { String[] f = {e,l,n,m,h,s,c,t,b,g,D,L,N,M,H,S,C,T,B,G,e,D,o,p,q,r,u,v,w,x}; int R=20,X=10,Y=100,Z=1000; return P==0?(_>0?d:e):(P<R?f[P]+Q:(P<Y?(f[R+(P/X)]+" "+a(P%X,0,e)).trim()+Q:(P<Z?a(P/Y,0,O)+a(P%Y,0,e)+Q:a(P/Z,0," thousand ")+ a((P/Y)%X,0,O)+a(P%Y,0,e)+Q))); } } 

Kommentarer

• Jag vet att det ' har gått mer än ett år, men du kan ta bort några parenteser i det ternära uppdraget samt ändra ==0 till <1. Så: return P<1?_>0?d:e:P<R?f[P]+Q:P<Y?(f[R+(P/X)]+" "+a(P%X,0,e)).trim()+Q:P<Z?a(P/Y,0,O)+a(P%Y,0,e)+Q:a(P/Z,0," thousand ")+a((P/Y)%X,0,O)+a(P%Y,0,e)+Q; ( – 10 byte )

JavaScript, 382 – 150 – 30 = 202 byte

var o=[0,3,3,5,4,4,3,5,5,4],f=s=>(s[1]==1?[3,6,6,8,8,7,7,9,8,8][s[0]]:o[s[0]]+(s.length>1?[0,3,6,6,5,5,5,7,6,6][s[1]]:0))+(s.length==3?(7+o[s[2]]-(o[s[2]]==0?7:0)):0),l=n=>{var s=(""+n).split("").reverse();return f(s.slice(0,3))+(s.length>3?(f(s.slice(3,6))+8):0)};(n=>{var s="";while(n!=4){s+=n+" is ";n=n>=0?l(n):(l(-n)+8);s+=n+" and ";}console.log(s+"4 is the magic number");})() 

Ingången ges som parameter för det omedelbart anropade funktionsuttrycket.

Testingång:

999999 -> 999999 is 50 and 50 is 5 and 5 is 4 and 4 is the magic number 17 -> 17 is 9 and 9 is 4 and 4 is the magic number -404 -> -404 is 23 and 23 is 11 and 11 is 6 and 6 is 3 and 3 is 5 and 5 is 4 and 4 is the magic number 

De-golf:

// array of the lengths of digits in ones place: // one is 3, two is 3, three is 5, etc... zero is a special case // and is assigned zero length because zero is never written out in a number name var o=[0,3,3,5,4,4,3,5,5,4], // function that computes the length of a substring of the input // because the input is 6 digits, it can be broken into two 3 digit subsections // each of which can have it"s length calculated separately f=s=> ( s[1]==1? // check for if the tens digit is a one // when the tens is a one, pull the string length from an array that represents // ten, eleven, twelve, thirteen, etc... [3,6,6,8,8,7,7,9,8,8][s[0]] : // when the tens digit is not a one, add the ones digit normally and... o[s[0]] + // add the tens digit length from the array that represents // zero, ten, twenty, thirty, forty, fifty, sixty, seventy, eighty, ninety (s.length>1?[0,3,6,6,5,5,5,7,6,6][s[1]]:0) ) + ( s.length==3? // check if the length is 3 and weren"t not accidentally trying to do something wierd with a minus sign // if so, then we have to add a hundred (7 characters) to the length and the // length of the ones digit that is in the hundreds place like // "one" hundred or "two" hundred (7+o[s[2]]- ( // also, if the hundreds place was a zero, subtract out those 7 characters // that were added because "hundred" isn"t added if there"s a zero in its // place o[s[2]]==0? 7 : 0 ) ) : // if the length wasn"t 3, then don"t add anything for the hundred 0 ), // function that computes the length of the whole six digit number l=n=>{ // coerce the number into a string and then reverse the string so that the // ones digit is the zeroth element instead of last element var s=(""+n).split("").reverse(); return // calculate the character length of the first 3 characters // like in the number 999888, this does the "888" f(s.slice(0,3)) + // then if there actually are any characters after the first 3 (s.length>3? // parse the character length of the second 3 characters (f(s.slice(3,6))+8) : 0 ) }; // lastly is the Immediately-Invoked Function Expression (n=>{ var s=""; // as long as we haven"t reached four, just keep going through the loop while(n!=4){ s+=n+" is "; n=n>=0?l(n):(l(-n)+8) // this handles negatives by only passing positive values to l and then just adding 8 onto the length for negatives s+=n+" and "; } // finally just say that "4 is the magic number" console.log(s+"4 is the magic number"); })(999999) 

Python 641-150 = 501 byte

Det är åtminstone inte längre än Java! Det är baserat på detta förutom att använda strängar.

EDIT : I glömde bort 0 och att jag måste säga " 5 är 4 ", inte hoppa till " 4 är det magiska numret " – som gav lite till poängen.

w={0:"zero",1:"one",2:"two",3:"three",4:"four",5:"five",6:"six",7:"seven",8:"eight",9:"nine",10:"ten",11:"eleven",12:"twelve",13:"thirteen",14:"fourteen",15:"fifteen",16:"sixteen",17:"seventeen",18:"eighteen",19:"nineteen",20:"twenty",30:"thirty",40:"forty",50:"fifty",60:"sixty",70:"seventy",80:"eighty",90:"ninety"} s="" def i(n): global s e="" o=n%10 t=n%100 h=n/100%10 th=n/1000 if th: e+=i(th) e+="thousand" if h: e+=w[h] e+="hundred" if t: if t<20 or o==0: e+=w[t] else: e+=w[t-o] e+=w[o] if len(e)==4:s+="4 is the magic number";print s else: s+="%d is %d and "%(n,len(e));i(len(e)) In=input() i(In) 

Prova det här!

Kommentarer

• Du behöver inte ' måste du visa namnet, eller hur?
• Detta är felaktigt. i(5) skriver ut 4 is the magic number istället för 5 is 4 and 4 is the magic number.

PHP, 168 – 30 = 138 byte

function m($i){$e=strlen(preg_replace("/[^a-z-]/","",(new NumberFormatter("en",5))->format($i)));echo($i==$e?"":"$i is $e and "),($e==4?"4 is the magic number":m($e));} 

Moo, 182 176 / 192 188 byte – 30 = 146/158

188 byteversion:

u=$string_utils;s="";i=args[1];while(i-4)j=u:english_number(i);s=s+j+(s?" and "+j|"")+" is ";i=length(u:strip_chars(j,"- "}));endwhile;return s+(s?"four and "|"")+"four is the magic number" 

176 byte implementeringsberoende version:

s="";i=args[1];while(i-4)j=#20:english_number(i);s=s+j+(s?" and "+j|"")+" is ";i=length(#20:strip_chars(j," -"));endwhile;return s+(s?"four and "|"")+"four is the magic number" 

Båda är funktioner.