Hvordan springer jeg uden for løkken? i nedenstående program, hvordan man bruger goto eller et hvilket som helst andet Jump-relateret program

const int analogPin1 = A1; const int analogPin2 = A2; const int analogPin3 = A3; const int ledPin = 13; const int ledPin2 = 7; const int thresold = 400; unsigned int x1, x2, x3, fault = 0; void setup() { pinMode(ledPin, OUTPUT); Serial.begin(9600); } void Config() { delay(1000); Serial.print("ATE0r"); Response(); Serial.print("ATr"); Response(); Serial.print("AT+CMGF=1r"); Response(); Serial.print("AT+CNMI=1,2,0,0,0r"); Response(); } void Response() { int count = 0; Serial.println(); while (1) { if (Serial.available()) { char data = Serial.read(); if (data == "K") { Serial.println("OK"); break; } if (data == "R") { Serial.println("GSM Not Working"); break; } } count++; delay(10); if (count == 1000) { Serial.println("GSM not Found"); break; } } } void loop() { int analogValue1 = analogRead(analogPin1); int analogValue2 = analogRead(analogPin2); int analogValue3 = analogRead(analogPin3); if (analogValue1 < thresold) { x1 = 1; fault = x1; } if (analogValue2 < thresold) { x2 = x1 + 3; fault = x2; } if (analogValue3 < thresold) { x3 = x1 + x2 + 5; fault = x3; } switch (fault) { case 1: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("PHASE 1 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); goto nsr; break; case 3: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("2 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); goto nsr; break; case 4: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("1 AND 2 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); goto nsr; break; case 5: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("3 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); Serial.print("AT+CNMI=2,2,0,0,0"); goto nsr; break; case 6: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("1 AND 3 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); goto nsr; break; case 8: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("2 AND 3 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); goto nsr; break; case 10: digitalWrite(ledPin, HIGH); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("ALL 3 HAS GONE"); delay(1000); Serial.write(0x1A); delay(1000); goto nsr; break; default: x1, x2, x3, fault = 0; digitalWrite(ledPin, LOW); break; } x1, x2, x3, fault = 0; digitalWrite(ledPin, LOW); do { int analogValue1 = analogRead(analogPin1); int analogValue2 = analogRead(analogPin2); int analogValue3 = analogRead(analogPin3); } while (analogValue1 < thresold || analogValue2 < thresold || analogValue3 < thresold); } do { int analogValue1 = analogRead(analogPin1); int analogValue2 = analogRead(analogPin2); int analogValue3 = analogRead(analogPin3); } while ((analogValue1 > th) && (analogValue2 > th) && (analogValue3 > th)); } nsr : if ((analogValue1 > th) && (analogValue2 > th) && (analogValue3 > th)) { digitalWrite(ledPin, HIGH); Serial.begin(9600); Serial.print("\r"); delay(1000); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("ALL 3 Phase Restored"); delay(1000); Serial.write(0x1A); delay(1000); Serial.print("\r"); delay(1000); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("ALL 3 Phase Restored"); delay(1000); Serial.write(0x1A); delay(1000); do { int analogValue1 = analogRead(analogPin1); int analogValue2 = analogRead(analogPin2); int analogValue3 = analogRead(analogPin3); } while ((analogValue1 > th) && (analogValue2 > th) && (analogValue3 > th)); } 

Kommentarer

  • Formatér din kode korrekt. Jeg kan ' ikke følge, hvad der går med hvad der.
  • Ja, grimt stykke spaghettikode (virkelig pænt sagt).
  • Og efter at have brugt C ++ formatter er det ' ret indlysende, hvorfor det kan ' t arbejder
  • Bare for nysgerrigheden skal x1, x2, x3, fault = 0; sætte disse variabler til nul? Jeg har dårlige nyheder til dig.

Svar

Du vil oprette en separat funktion nsr og brug det i stedet for at gå.

void nsr(void){ if ((analogValue1 > th) && (analogValue2 > th) && (analogValue3 > th)) { digitalWrite(ledPin, HIGH); Serial.begin(9600); Serial.print("\r"); delay(1000); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("ALL 3 Phase Restored"); delay(1000); Serial.write(0x1A); delay(1000); Serial.print("\r"); delay(1000); Serial.print("AT+CMGF=1\r"); delay(1000); Serial.print("AT+CMGS=\"+919\"\r"); delay(1000); Serial.print("ALL 3 Phase Restored"); delay(1000); Serial.write(0x1A); delay(1000); do { int analogValue1 = analogRead(analogPin1); int analogValue2 = analogRead(analogPin2); int analogValue3 = analogRead(analogPin3); } while ((analogValue1 > th) && (analogValue2 > th) && (analogValue3 > th)); } } 

Svar

I stedet for at bruge

goto nsr 

Brug en boolsk til at springe dele over, som du ikke vil udføre. Det er (næsten) aldrig en god ide at bruge goto.

På grund af forkert justering af {og} ved jeg ikke, hvad du nøjagtigt vil udføre.

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